How many terms of the A.P. 7, 11, 15, 19_____ must be taken to get the sum 297? Question How many terms of the A.P. 7, 11, 15, 19_____ must be taken to get the sum 297? in progress 0 Math Maria 1 month 2021-08-22T23:11:28+00:00 2021-08-22T23:11:28+00:00 1 Answer 0 views 0

## Answers ( )

Answer:Let the number of terms be ‘n’

n/2(2×7(n-1)4)=297

n(7+2n-2)=297

2n^2+5n-297=0

2n^2+27n-22n-297=0

n(2n-27)-11(2n-27)=0

(n-11)(2n-27)=0

n=11 or n=27/2

Required number of terms=11

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