If 11^2, 3^4 and 2^5 are the factors of a x 12^7 x 17^6 x 21^5 then what is the minimum possible value of a

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If 11^2, 3^4 and 2^5 are the factors of a x 12^7 x 17^6 x 21^5 then what is the minimum possible value of a

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Hailey 2 months 2021-10-09T19:19:50+00:00 2 Answers 0 views 0

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    0
    2021-10-09T19:20:52+00:00

    nagavajbznzb

    Answer:

    bbxbxbbxbxhsbsjakajavzbsgsnhsaha

    0
    2021-10-09T19:21:36+00:00

    Step-by-step explanation:

    Step 1 of solving this GMAT Number Properties Question: Prime factorize the given expression

    a * 43 * 62 * 1311 can be expressed in terms of its prime factors as a * 28 * 32 * 1311

    Step 2 of solving this GMAT Number Properties Question: Find factors missing after excluding ‘a’ to make the number divisible by both 112 and 33

    112 is a factor of the given number.

    If we do not include ‘a’, 11 is not a prime factor of the given number.

    If 112 is a factor of the number, 112 should be a part of ‘a’

    33 is a factor of the given number.

    If we do not include ‘a’, the number has only 32 in it.

    Therefore, if 33 has to be a factor of the given number ‘a’ has to contain 31 in it.

    Therefore, ‘a’ should be at least 112 * 3 = 363 if the given number has 112 and 33 as its factors.

    The question is “what is the smallest possible value of ‘a’?”

    The smallest value that ‘a’ can take is 363

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