If x^3 – 3kx + 8 is divisable by x-2 then value of k is

Question

If x^3 – 3kx + 8 is divisable by x-2 then value of k is

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Anna 3 weeks 2021-08-20T10:43:55+00:00 1 Answer 0 views 0

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    2021-08-20T10:45:07+00:00

    Answer:

    k=8/3

    Step-by-step explanation:

    If x-2 is divisible by x^3-3kx+8, then x-2 is a factor

    therefore x=2

    p(x)=0

    p(2)=(2)^3-3k(2)+8=0

            8-6k+8=0

            16-6k=0

                -6k=-16

                    k=-16/-6

                    k=8/3

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