if x=3a3+3a+5a2+8,y=3a2+5a3-4a+1 and z=7-7a+6a3-4a2, then find x+y-z

Question

if x=3a3+3a+5a2+8,y=3a2+5a3-4a+1 and z=7-7a+6a3-4a2, then find x+y-z

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Maya 2 weeks 2021-09-09T03:42:27+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-09T03:43:46+00:00

    I don’t know the answer

    0
    2021-09-09T03:44:19+00:00

    Answer:

    as x ,y and z are given

    now we have to find x+y-z ?

    so put the value of x, y and z

    x+y-z= (3a3+3a+5a2+8)+(3a2+5a3-4a+1)-(7-7a+6a3-4a2)

    =(8a3+8a2-a+9)-7+7a-6a3+4a2

    =2a3+12a2+6a+2

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