if a+ b = 10 and a square + b square =58 , find the value of a-b and a square – b square​

Question

if a+ b = 10 and a square + b square =58 , find the value of a-b and a square – b square​

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Quinn 1 month 2021-10-27T01:40:23+00:00 1 Answer 0 views 0

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    2021-10-27T01:41:51+00:00

    Answer:

    a+b = 10

    b= 10- a ——> eqn ☺️

    put in a^2+b^2= 58

    ( 10-b) ^2 + b^2 = 58

    100+ b^2 – 20b + b^2 = 58

    2b^2 – 20b = 58-100

    2( b^2 – 10b) = -42

    now divide by 2 on both sides

    b^2 – 10b = – 21

    b^2 – 10b + 21 = 0

    b^2 -7 b -3b + 21 = 0

    b ( b -7 ) – 3( b – 7 ) = 0

    now ,

    b= 7 whn a= 3

    b= 3 whn a = 7

    as a.> b here so a= 7 and b = 3

    and

    .

    . . a-b = 4 and

    a^2 – b^2 = 40

    hope this answer will be helpful to you

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