If a+b=3 and ab=2 then find the value of (a-b)2

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If a+b=3 and ab=2 then find the value of (a-b)2

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Melody 1 month 2021-08-23T06:10:09+00:00 2 Answers 0 views 0

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    0
    2021-08-23T06:11:20+00:00

    Step-by-step explanation:

    (a-b)2 = (a+b) (a-b)

    We have the value of a+b=3 and the value of ab=2.

    We have to find the value of a-b=?

    Let , a+b=3———(1) equation

    ab=2——(2) equation

    Now take eq. 1 and find the value of b, b=(3-a).

    Put this value of b in the eq. (1) ,

    a(3-a)=2

    3a-a^2=2

    a^2–3a+2=0, this is square equation so it has two value and when we factorized it we got,

    a^2–2a-a+2=0

    a(a-2)-1(a-2)=0

    (a-1)(a-2)=0

    It means that (a-1) & (a-2) both are the factors of a^2–2a-a+2.

    We got two value of a =1 & 2

    Condition 1. When a=1 then b=2

    Condition 1. When a=1 then b=2Condition 2. When a=2 then b=1. Answer

    pls Mark as brainliest

    0
    2021-08-23T06:12:03+00:00

    \huge\boxed{\underline{\underline{\green{\tt Solution}}}}

    We are aware of the identity

    (a - b)² =  (a + b)² - 4ab

     \implies \: (a - b)² =  (3)² - 4 \times 2 = 9 - 8 = 1

    \displaystyle\textcolor{red}{Please \:  Mark \:  it  \: Brainliest}

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