If (a + b + c) = 5 and (ab + bc + ca = 10) then prove that ( a + + – 3abc = -25) Answer karo! Fastttttttttttt

Question

If (a + b + c) = 5 and (ab + bc + ca = 10) then prove that ( a + + – 3abc = -25)

Answer karo!

Fastttttttttttt

– Utkarsh Pratham here!

Ex Proficient!​

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1 month 2021-08-13T04:00:07+00:00 2 Answers 0 views 0

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    0
    2021-08-13T04:01:12+00:00

    \large\sf\underline{\underline{\red{Correct \ Question}}}

    If a + b + c = 5 and ab+bc+ca= 10 then prove that a² + b² + c² – 3abc = -25

    \huge\sf\blue{Given}

    ✭ a+b+c = 5

    ✭ ab+bc+ca = 10

    \rule{110}1

    \huge\sf\gray{To \:Find}

    ◈ a² + b² + c² – 3abc = -25

    \rule{110}1

    \huge\sf\purple{Steps}

    Before Solving we should know the formula,

    \underline{\boxed{\sf (a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca}}

    Substituting the given values,

    \sf 5^2 = a^2+b^2+c^2+2(ab+bc+ca)

    \sf 25 = a^2+b^2+c^2+2(10)

    \sf 25 = a^2+b^2+c^2+20

    \sf 25-20 = a^2+b^2+c^2

    \sf 5 = a^2+b^2+c^2

    \sf\bigg\lgroup (a+b+c)(a^2+b^2+c^2)-(ab+bc+ca)\bigg\rgroup

    \sf (5)(5-10)

    \sf \orange{-25}

    \sf LHS = RHS

    \sf Hence \ Proved!!

    \rule{170}3

    0
    2021-08-13T04:02:04+00:00

    Answer:

    this is your answer

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    Step-by-step explanation:

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