If a+b+c=9 and ab+bc+ca = 26 find a2 + b2 + c2 and a3 + b3 + c3 – 3abc

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If a+b+c=9 and ab+bc+ca = 26 find a2 + b2 + c2 and a3 + b3 + c3 – 3abc

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Charlie 4 months 2022-01-06T17:18:14+00:00 1 Answer 0 views 0

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    2022-01-06T17:20:07+00:00

    Answer:

    a² + b² + c² = 29 and a³ + b³ + c³ – 3abc = 27

    Step-by-step explanation:

    a + b + c = 9

    ab + bc + ac = 26

    Find a² + b² + c² and a³ + b³ + c³ – 3abc

    We know , (a + b + c)² = a² + b² + c² + 2(ab + bc + ac)

    9² = a² + b² + c² + 2(26)

    a² + b² + c² = 81 – 52

    a² + b² + c² = 29

    We know , (a + b + c)³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ac)

    = 9 ( 29 – 26)

    = 9 x 3

    = 27

    Hope you get it…

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