If d is HCF of 120 and 156 then express d= 120 x+ 156y

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If d is HCF of 120 and 156 then express d=
120 x+ 156y

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4 weeks 2021-11-03T18:50:01+00:00 1 Answer 0 views 0

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  1. Ava
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    2021-11-03T18:51:04+00:00

    Given : d is HCF of 120 and 156  

    To Find : express d= 120 x+ 156y

    Solution:

    HCF of 120 and 156  

    156 = 120 x 1  + 36

    120 = 36 x 3  + 12

    36 = 12 x 3  

    12 is the HCF

    120 = 36 x 3  + 12 from this

    12 = 120  – 36 x 3

    156 = 120 x 1  + 36 from this  

    36 = 156 – 120

    12 = 120  –  (156 – 120) x 3

    => 12 = 120 – 156 x 3 + 120 x 3

    => 12 = 120 x 4  – 150 x 3

    => 12 = 120 x 4  + 150 x (-3)

    d= 120 x+ 156y

    d = 12

    x = 4

    y = 3

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