## If each sife of a cube increases 50% by length then what is the percentage increase in total surface area of the cube

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## Answers ( )

answer = 125%

let the length of one side be 2cm

then surface area = 6*2*2*= 24 sq metre

after 50% increase the side becomes 3 cm

then surface area = 6*3*3=54

percentage increase =(54-24) /24*100= 30/24*100

= 125%

Answer:After 50% increase, each edge of the cube becomes 150/100 of the original. Thus, the surface area of the cube becomes (150/100)^2 = 225/100 of the original. Hence, increase in perecentage of surface area = (225-100) = 125% .

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