If each sife of a cube increases 50% by length then what is the percentage increase in total surface area of the cube

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If each sife of a cube increases 50% by length then what is the percentage increase in total surface area of the cube

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Alexandra 4 weeks 2021-08-16T10:50:16+00:00 2 Answers 0 views 0

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    2021-08-16T10:51:40+00:00

    answer = 125%

    let the length of one side be 2cm

    then surface area = 6*2*2*= 24 sq metre

    after 50% increase the side becomes 3 cm

    then surface area = 6*3*3=54

    percentage increase =(54-24) /24*100= 30/24*100

    = 125%

    0
    2021-08-16T10:51:58+00:00

    Answer:

    After 50% increase, each edge of the cube becomes 150/100 of the original. Thus, the surface area of the cube becomes (150/100)^2 = 225/100 of the original. Hence, increase in perecentage of surface area = (225-100) = 125% .

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