If one root of the equation x^2-px+8=0 is twice the other then p= Question If one root of the equation x^2-px+8=0 is twice the other then p= in progress 0 Math Mackenzie 4 weeks 2021-08-18T14:01:23+00:00 2021-08-18T14:01:23+00:00 1 Answer 0 views 0

## Answers ( )

Answer:sum of root(a+b)=p—————————–1

multiple of roots ab=8———————-2

according to question a=2b —————-3

put the value of a in ——-2

2b x b =8

2 b^2 =8

b^2=4

b=2,-2

put the value of b in —————3

then a= 2 x 2 =4

and a= -2 x 2= -4

hence we have a=4, b=2 and a=-2 , b=-4 put this value in —————–1

we have 2+4 = p

so , p=6

and -2 + -4 =p

so p= -6

so the correct answer is p = -6

Step-by-step explanation: