If one root of the equation x^2-px+8=0 is twice the other then p=

Question

If one root of the equation x^2-px+8=0 is twice the other then p=

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Mackenzie 4 weeks 2021-08-18T14:01:23+00:00 1 Answer 0 views 0

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    2021-08-18T14:02:32+00:00

    Answer:

    sum of root(a+b)=p—————————–1

    multiple of roots ab=8———————-2

    according to question a=2b —————-3

    put the value of a in ——-2

    2b x b =8

    2 b^2 =8

    b^2=4

    b=2,-2

    put the value of b in —————3

    then a= 2 x 2 =4

    and a= -2 x 2= -4

    hence we have a=4, b=2 and a=-2 , b=-4 put this value in —————–1

    we have 2+4 = p

    so , p=6

    and -2 + -4 =p

    so p= -6

    so the correct answer is p = -6

    Step-by-step explanation:

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