if p(x,y) is the midpoint of the line segment joining the points A(1,3) and (-2,6) then x+y is ​

Question

if p(x,y) is the midpoint of the line segment joining the points A(1,3) and (-2,6) then x+y is

in progress 0
Ximena 3 weeks 2021-11-06T23:27:55+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-06T23:28:55+00:00

    Given :-

    P(x, y) is the mid point of the line segment joining the points A(1,3) and (-2,6).

    To Find:

    The value of x + y

    \underline{\bigstar{\sf{\ \ Solution: -\ \ }}}

    First we have to find the mid point of the line segment.

    Let the mid point be “M”.

    We know that,

    \bullet\sf Mid \ point (M) =\dfrac{ (x_1 + x_2) }{2} ,\dfrac{ (y_1 + y_2)}{2}

    From the above points,

    \sf\bullet  x_1 = 1  \\ \bullet\sf y_1 = 3 \\ \bullet\sf \ x_2 = -2\  \\   \bullet\sf \   y_2 = 6

    \implies\sf  ( M )=\dfrac{ [1 + (-2) ]}{2} \ ,\  \dfrac{(3 + 6)}{2}\\ \\ \implies\sf M =\dfrac{ (1 - 2) }{2}\  , \ \dfrac{ 9}{2} \\ \\ \implies\sf M = \dfrac{-1 }{2}\  ,\  \dfrac{9}{2}\\ \\ \implies\sf Mid point = \dfrac{-1}{2 }\ , \ \dfrac{9}{2}

    Now,

    \implies\sf (x + y) =\dfrac{ -1}{2 }+\dfrac{ 9}{2 }\\ \\ \implies\sf x+y= \cancel{\dfrac{8}{2}} \\ \\ \implies\sf x+y= 4

    \underline{\sf{\therefore\ \  the \ value \ of \ x + y\  is  \ 4\  units.}}

    0
    2021-11-06T23:28:57+00:00

    Answer:

    p(x,y) = [(x1+X2)/2, (y1+y2)/2]

    = [{ 1+(-2)}/2, (3+6)/2 ]

    = (-1/2, 9/2)

    therefore x = -1/2 and y = 9/2

    x + y = -1/2 + 9/2

    = (-1 + 9)/2

    = 8/2

    = 4

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )