If sin (A+B)=1 and tan(A-B)=1/√3,find the value of tan A+ cot B

Question

If sin (A+B)=1 and tan(A-B)=1/√3,find the value of tan A+ cot B

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Evelyn 3 weeks 2021-10-01T16:41:34+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-01T16:42:54+00:00

    Step-by-step explanation:

    at first we know A+B=90,thenA_B =30,then adding two equation we get A ,therefore putting A, we get B

    0
    2021-10-01T16:43:17+00:00

    Answer:

    Step-by-step explanation:

    Sin(A+B)=sin90

    So A+B=90

    Tan(A-B)=tan 30

    So A-B=30

    Solving the 2 equation we have

    A=60 B=30

    Now Tan A + Cot B =Tan 60 + Cot 30

    =√3+√3

    =2√3

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