if the angles a b c are in a.p. then sinA+sinC/cosA +cosc in angle​

Question

if the angles a b c are in a.p. then sinA+sinC/cosA +cosc in angle​

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Alexandra 2 months 2021-09-25T06:42:29+00:00 1 Answer 0 views 0

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    2021-09-25T06:43:45+00:00

    Answer:

    Given that in ΔABC , ∠A,∠B,∠C are in increasing A.P. then we have

    ∠B−∠A=∠C−∠B

    2∠B=∠A+∠C

    But, in ΔABC , ∠A+∠B+∠C=π⟹∠A+∠C=π−∠B

    2∠B=π−∠B

    3∠B=π

    ∠B=π3

    ∴sinB=sinπ3=3√2

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