if the first term of an A.P is 2 and common difference is 4 then the sum of its first 40 terms is? Question if the first term of an A.P is 2 and common difference is 4 then the sum of its first 40 terms is? in progress 0 Math Maya 2 months 2021-08-14T01:26:21+00:00 2021-08-14T01:26:21+00:00 2 Answers 0 views 0

## Answers ( )

Answer:a=2

d=4

n=40

Sn=?

Sn=n/2×{2a+(n-1) d}

Sn= 40/2 ×{2×2+39×4}

Sn=20×160

Sn=320

therefore sum of 40 terms is 320

Answer:Sn =[2a+ (n-1)d]

n2

n= 40 ; a= 2 ; d = 4

S40 =[2×2 + ( 40 – 1) ×4 ]

402

= 20 [ 4 + ( 39× 4) ]

= 20 [ 4 + 156]

= 20 × 160

= 3200 ANS.

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