If the HCF of 210 and 55 is expressible in form 210×5+55y,find Y

Question

If the HCF of 210 and 55 is expressible in form 210×5+55y,find Y

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Adalynn 5 months 2021-12-10T18:07:28+00:00 1 Answer 0 views 0

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    2021-12-10T18:08:34+00:00

    Answer:

    Step-by-step explanation:

    we know the formula a = bq + r

    210 = 55 × 3 +45 say it is eq . 1)

    55 = 45 ×1 + 10 2)

    45 = 4×10 +5 3)

    now we consider the divisor 10 and the remainder 5 and apply DL to get

    10 = 5×2 +0

    we observe here that r =0 and our present divisor which is 5 will be it HcF

    A/Q

    5 = 210 ×5 + 55y

    55y = 5 – 210×5

    = 5 – 1050

    y = – 1045 /55

    y=-19

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