If the point (3, 4) lie on the graph of the linear equation 3y = kx + 6, then find the value of k.​

Question

If the point (3, 4) lie on the graph of the linear equation 3y = kx + 6, then find
the value of k.​

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Caroline 3 weeks 2021-10-01T21:38:04+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-01T21:39:26+00:00

    Answer:

    Since, the point (x = 3, y = 4) lies on the equation 3y = kx + 7

    then the equation will be , satisfied by the point.

    Now, put x = 3 and y = 4 in given equation, we get

    3(4) = k (3)+7

    ⇒ 12 = 3k+7

    ⇒ 3k = 12 – 7

    ⇒ 3k = 5

    Hence, the value of k is 5/3.

    0
    2021-10-01T21:39:35+00:00

    value of k = 2……………..

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