If the squared difference of the zeros of the quadratic polynomial f(x) = x2+px +45 is equal to 144, find the value of p ​

Question

If the squared difference of the zeros of the quadratic polynomial f(x) = x2+px +45 is
equal to 144, find the value of p

in progress 0
Madeline 1 month 2021-08-14T04:19:52+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-14T04:21:15+00:00

    Answer: p = +18 or -18

    Step-by-step explanation:

    x^2 +px+45 =0

    Let roots be a and b

    hence, sum of roots (a+b) = p and product of roots (ab) = 45

     

    Now, (a-b)^2  = 144

    (a+b)^2 – 4ab = 144

    p^2 – 4*45 = 144

    p^2 = 324

    p = +18 or -18

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )