If the sum of the AP 3, 7, 11, = is 210, then the number of terms in this AP is The sum of first in​

Question

If the sum of the AP 3, 7, 11, — is 210, then the number of terms in this AP is
The sum of first in​

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Hailey 1 month 2021-08-14T12:01:24+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-14T12:02:44+00:00

    Step-by-step explanation:

    given AP 3,7,11,15,19…..

    Sum of terms = 210

    Let us say number of terms is n.

    Hence sum= n(2a+(n-1)d)/2

    Now, first term = a = 3

    d= common difference = 7-3 = 4

    putting these values we get

    210=n(6+4(n-1))/2

    210 = n(3+2n-2)

    210= n(2n +1)

    2n2 + n -210 = 0

    2n2 + 21n-20n-210 = 0

    n(2n+21)-10(2n-21) = 0

    (n-10)(2n+21)=0

    So, n = 10 or n =-21/2, it can not be n because n is number of terms that can not be negative.

    So correct value is n=10

    2) Sum of first n terms of AP, Sn = 3n2 + 2n

    Now choose n =1 and put in the above formula since

    this means sum of first 1 term that is the first term only = 3+2 = 5

    Now put n=2 to get the sum of first two terms = 3×4 + 2×2 = 12+4 = 16

    This means

    first term + second term = 16

    but first term =5 as calculated above

    so, second term = 16-5 = 11

    So common difference becomes, 11-5 = 6

    So the AP becomes, 5, 11, 17, 23……

    0
    2021-08-14T12:03:02+00:00

    Answer:

    We know that nth term tn = sum of of the first n terms – sum of the first n-1 terms= 210–171 = 39.

    But tn = a+ (n-1)d = 39 => 3+(n-1)d = 39

    => (n-1)d = 39–3= 36. ………(1)

    Now And = (n/2){2a+(n-1)d} = 210

    => (n/2){6+36} = 210 (using (1))

    => (n/2)(42)= 210 => n/2 = 210/42=5 => n= 2×5=10

    Using n=10 in(1) we get (10–1)d = 36

    => d = 36/9= 4

    So the AP is 3,7,11,15,……

    mark as brainliest..

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