if the value of 1^2+2^2+3^2+==–10^2=P then calculate 2^2+4^2+6^2+==20^2=?​

Question

if the value of 1^2+2^2+3^2+——–10^2=P then calculate 2^2+4^2+6^2+——20^2=?​

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Elliana 1 week 2021-09-14T06:19:48+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-14T06:21:29+00:00

    Step-by-step explanation:

    check out the attached picture..answer is there

    0
    2021-09-14T06:21:46+00:00

    Answer:

    If we multiply 4 in both sides of the first equation,

    we get (2×1)^2 + (2×2)^2 + (2×3)^2 +________+(2×10)^2 = 4P

    So your answer is 4P

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