If two parallel lines are interested by a transversal,prove that the bisector of the two pairs of interior angles enclose a rectangle

Question

If two parallel lines are interested by a transversal,prove that the bisector of the two pairs of interior angles enclose a rectangle

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Parker 3 days 2021-09-13T20:30:17+00:00 2 Answers 0 views 0

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    2021-09-13T20:31:30+00:00

    Answer:

    AB and CD are two parallel lines intersected by a transversal L. X and Y are the points of intersection of L with AB and CD respectively. XP, XQ, YP and YQ are the angle bisectors of ∠ AXY, ∠ BXY, ∠ CYX and ∠ DYX.

    AB || CD and L is transversal.

    ∴ ∠ AXY = ∠ DYX (Pair of alternate angles)

    ⇒ 1/2 ∠ AXY = 1/2 ∠ DYX

    ⇒ ∠ 1 = ∠ 4 (∠ 1 = 1/2 ∠ AXY and ∠ 4 = 1/2 ∠ DYX)

    ⇒ PX/YQ (If a transversal intersects two lines in such a way that a pair of alternate interior angles are equal, then the two lines are parallel)…(1)

    Also ∠ BXY = ∠ CYX (Pair of alternate angles)

    ⇒ 1/2 ∠ BXY = 1/2 ∠ CYX

    ⇒ ∠ 2 = ∠ 3 (∠ 2 = 1/2 ∠ BXY and ∠ 3 = 1/2 ∠ CYX)

    ⇒ PY/XQ (If a transversal intersects two lines in such a way that a pair of alternate interior angles are equal, then the two lines are parallel) …(2)

    From (1) and (2), we get

    PXQY is a parallelogram ….(3)

    ∠ CYD = 180°

    ⇒ 1/2 ∠ CYD = 180/2 = 90°

    ⇒ 1/2 (∠CYX + ∠ DYX) = 90°

    ⇒ 1/2 ∠ CYX + 1/2 ∠ DYX = 90°

    ⇒ ∠3 + ∠ 4 = 90°

    ⇒ ∠ PYQ = 90° …(4)

    So, using (3) and (4), we conclude that PXQY is a rectangle.

    Hence proved.

    0
    2021-09-13T20:31:43+00:00

    Answer:

    Step-by-step explanation:

    AB and CD are two parallel lines intersected by a transversal L. X and Y are the points of intersection of L with AB and CD respectively. XP, XQ, YP and YQ are the angle bisectors of ∠ AXY, ∠ BXY, ∠ CYX and ∠ DYX.

    AB || CD and L is transversal.

    ∴ ∠ AXY = ∠ DYX (Pair of alternate angles)

    ⇒ 1/2 ∠ AXY = 1/2 ∠ DYX

    ⇒ ∠ 1 = ∠ 4 (∠ 1 = 1/2 ∠ AXY and ∠ 4 = 1/2 ∠ DYX)

    ⇒ PX/YQ  (If a transversal intersects two lines in such a way that a pair of alternate interior angles are equal, then the two lines are parallel)…(1)

    Also ∠ BXY = ∠ CYX  (Pair of alternate angles)

    ⇒ 1/2 ∠ BXY = 1/2 ∠ CYX

    ⇒ ∠ 2 = ∠ 3  (∠ 2 = 1/2 ∠ BXY and ∠ 3 = 1/2 ∠ CYX)

    ⇒ PY/XQ  (If a transversal intersects two lines in such a way that a pair of alternate interior angles are equal, then the two lines are parallel) …(2)

    From (1) and (2), we get

    PXQY is a parallelogram ….(3)

    ∠ CYD = 180°

    ⇒ 1/2 ∠ CYD = 180/2 = 90°

    ⇒ 1/2 (∠CYX + ∠ DYX) = 90°

    ⇒ 1/2 ∠ CYX + 1/2 ∠ DYX = 90°

    ⇒ ∠3 + ∠ 4 = 90°

    ⇒ ∠ PYQ = 90° …(4)

    So, using (3) and (4), we conclude that PXQY is a rectangle.

    Hence proved.

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