(ii) A ABC is an equilateral triangle. A ACD is an isosceles triangle with AC = CD, ZCAD = 5x + 15°. Find x. ​

Question

(ii) A ABC is an equilateral triangle.
A ACD is an isosceles triangle with AC = CD, ZCAD = 5x + 15°. Find x.

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Arianna 1 month 2021-08-20T05:44:08+00:00 2 Answers 0 views 0

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    0
    2021-08-20T05:45:33+00:00

    Step-by-step explanation:

    Given A ABC is an equilateral triangle. A ACD is an isosceles triangle with AC = CD, angle CAD = 5x + 15°. Find x

    • Angle ABC is an equilateral triangle.
    • Angle ACD is an isosceles triangle
    • Also AC = CD
    • Given angle CAD = 5x + 15 at point C
    • So angle ABC = angle ACB = 60 degree
    • We have at point C we get
    • So 5x + 15 + 60 = 180  
    •      5x + 75 = 180
    •      5x = 180 – 75
    •       5x = 105
    •      Or x = 105 / 5
    •     Or x = 21 degree

    Reference link will be

    https://brainly.in/question/2835904

    0
    2021-08-20T05:45:53+00:00

    Answer:

    please dont delete my answers they are correct please

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