In a right angle triangle ABC right angle at C. BC +CA= 23 cm and BC-CA= 7 . Then find sin A and tan B I will mark as brainlist​

Question

In a right angle triangle ABC right angle at C. BC +CA= 23 cm and BC-CA= 7 . Then find sin A and tan B
I will mark as brainlist​

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Sarah 1 month 2021-08-13T00:56:46+00:00 2 Answers 0 views 0

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    0
    2021-08-13T00:58:02+00:00

    Answer:

    BC+CA=23

    BC-CA  = 7

    Adding these two equations

    2BC=30

    BC=15

    Substituting this value in the first equation

    15+CA=23

    CA=8

    BC^{2}BC2 +AC^{2}AC2 =AB^{2}AB2 (by pythagorus theorem)

    ⇒(15*15)+(8*8)=AB^{2}AB2

    225+64=AB^{2}AB2

    AB^{2}AB2 =289

    ⇒AC=17

    Now,

    SinA= 15/17

    tanB = 8/15

    Hope it helps…

    0
    2021-08-13T00:58:35+00:00

    Answer:

    see this image ……………………

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