In a right angle triangle ABC, right angle is at C. BC + CA = 23 cm and BC-CA= 7cm, then find sin A and tan B.​

Question

In a right angle triangle ABC, right angle is at C. BC + CA = 23 cm and
BC-CA= 7cm, then find sin A and tan B.​

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Ximena 4 weeks 2021-08-17T08:36:36+00:00 1 Answer 0 views 0

Answers ( )

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    2021-08-17T08:37:47+00:00

    Answer:

    Sin A = 15/17

    Tan A = 8/15

    Step-by-step explanation:

    Given

    BC+CA =23

    BC-CA = 7

    Proof

    BC= 7+CA

    Putting the value in BC+CA =23

    7+CA+CA = 23

    2CA=23-7

    2CA =16

    CA = 16/2

    CA = 8

    BC= 7+8

    = 15

    (H)^2 = (P)^2 + (B)^2

    ” = (8)^2 + (15)^2

    ” = 64+225

    ” = 289

    H = 17

    Sin A = BC/AB = 15/17

    Tan B = AC/BC. = 8/15

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