in a triangle abc angle a equal to theta angle b equal to 90 degree angle c equal to phi bc equal to x is equal to x + 2 find the value of r

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in a triangle abc angle a equal to theta angle b equal to 90 degree angle c equal to phi bc equal to x is equal to x + 2 find the value of root x + 1 by root x cube + x square 10 theta cos theta

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Brielle 1 month 2021-08-13T00:41:09+00:00 1 Answer 0 views 0

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    2021-08-13T00:43:08+00:00

    Answer: BD= 13.25

    Step-by-step explanation: since in triangle ABCsine theta =5/13=perpendicular/hypotniousi,e AB/Ac=5/134/AC= 5/13AC=10.4Now in triangle EDCCOS phi= Base/hypotniousCD/CE = 3/5CD=(3/5)CEBy Pythagoras theoremCE=there fore CD = (3/5)√22.5= 2.84therefore BD= BC+CDBD=10.4+2.84BD= 13.25

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