In a triangle ABC B is 90° ABis 12 cm BC=5cm Find (1) cosa c (ii)cosec A, (iii) cos c (iv)cosec c ​

Question

In a triangle ABC
B is 90° ABis
12 cm BC=5cm
Find (1) cosa c (ii)cosec A, (iii) cos c (iv)cosec c

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Gabriella 5 months 2021-12-21T20:45:43+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-12-21T20:47:04+00:00

    Answer:

    cos a = 12/13

    cosec a = 13/5

    cos c = 5/13

    cosec c = 13/12

    Step-by-step explanation:

    as it’s given B= 90°

    so use the pythagoras theoram..

    ac^2 = Ab^2 + BC^2

    = 12^2 + 5^2

    = 144 + 25

    AC^2 = 169

    Ac= √169

    AC = 13

    cos a = base/Diagonal = AB/CA = 12/13

    cosec A = Diagonal/perpendicular = CA/BC = 13/5

    cos c = base/Diagonal = BC/CA = 5/13

    cosec C =Diagonal/perpendicular= CA/AB = 13/ 12

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