In Fig. 11.53, AB is the longest side and DC is the shortest side of a quadrilateral ABCD. Prove that ∠C > ∠A and ∠D> ∠B. [Hint Question In Fig. 11.53, AB is the longest side and DC is the shortest side of a quadrilateral ABCD. Prove that ∠C > ∠A and ∠D> ∠B. [Hint : Join AC and BD]. in progress 0 Math Kinsley 3 weeks 2021-09-07T04:02:43+00:00 2021-09-07T04:02:43+00:00 1 Answer 0 views 0

## Answers ( )

Answer:Given:In quadrilateral ABCD, AB smallest & CD is longest sides.To Prove: ∠A>∠C& ∠B>∠DConstruction: Join AC.Mark the angles as shown in the figure..Proof:In △ABC , AB is the shortest side.BC > AB∠2>∠4 …(i)[Angle opposite to longer side is greater]In △ADC , CD is the longest sideCD > AD∠1>∠3 …(ii)[Angle opposite to longer side is greater]Adding (i) and (ii), we have∠2+∠1>∠4+∠3⇒∠A>∠CSimilarly, by joining BD, we can prove that∠B>∠DPlease mark as the brainliest answer…………………………….