## in th 10. Two poles of equal heights are standing opposite each other on either side of the which is 80 m wide. From a point betwe

Question

in th
10. Two poles of equal heights are standing opposite each other on either side of the
which is 80 m wide. From a point between them on the road, the angles of elevati
the top of the poles are 60 and 30%, respectively. Find the height of the poles and
distances of the point from the poles.
1​

in progress 0
1 month 2021-08-13T04:35:37+00:00 2 Answers 0 views 0

don knoe

Step-by-step explanation:

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2. Step-by-step explanation:

Given that:

∠APB=60

,∠CPD=30

,AC=80m

To find:

The height of the pole=AB=CD=?

Solution:

Let AB and CD be the two poles of equal height and P be the point on the road between the poles.

In △APB,

tan60

=

AP

AB

or, AP=AB×

tan60

1

or, AP=

3

AB

−−−−−−−(i)

In △PCD,

tan30

=

CP

CD

or, CP=CD×

tan30

1

or, CP=

3

CD=

3

AB ∵AB=CD −−−−−−−(ii)

Adding eqn. (i) and eqn. (ii) we get,

AP+CP=

3

AB

+AB

3

or, AC=AB(

3

+

3

1

)

or, 80m=4

3

AB

or, AB=20

3

m

Therefore, height of the pole=20

3

m=34.64m