in th 10. Two poles of equal heights are standing opposite each other on either side of the which is 80 m wide. From a point betwe

Question

in th
10. Two poles of equal heights are standing opposite each other on either side of the
which is 80 m wide. From a point between them on the road, the angles of elevati
the top of the poles are 60 and 30%, respectively. Find the height of the poles and
distances of the point from the poles.
1​

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Jade 1 month 2021-08-13T04:35:37+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-13T04:36:51+00:00

    Answer:

    don knoe

    Step-by-step explanation:

    hgsghgbbpyytredhjnbvgdfxx

    0
    2021-08-13T04:37:24+00:00

    Step-by-step explanation:

    Given that:

    ∠APB=60

    ,∠CPD=30

    ,AC=80m

    To find:

    The height of the pole=AB=CD=?

    Solution:

    Let AB and CD be the two poles of equal height and P be the point on the road between the poles.

    In △APB,

    tan60

    =

    AP

    AB

    or, AP=AB×

    tan60

    1

    or, AP=

    3

    AB

    −−−−−−−(i)

    In △PCD,

    tan30

    =

    CP

    CD

    or, CP=CD×

    tan30

    1

    or, CP=

    3

    CD=

    3

    AB ∵AB=CD −−−−−−−(ii)

    Adding eqn. (i) and eqn. (ii) we get,

    AP+CP=

    3

    AB

    +AB

    3

    or, AC=AB(

    3

    +

    3

    1

    )

    or, 80m=4

    3

    AB

    or, AB=20

    3

    m

    Therefore, height of the pole=20

    3

    m=34.64m

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