locus of P such A(16) & B (3,5). Find equartion of locus of P such that angleAPB is that right angled. ​

Question

locus of P such
A(16) & B (3,5). Find equartion of locus of P such
that angleAPB is that right angled.

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Melanie 1 month 2021-09-17T07:42:39+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-17T07:43:44+00:00

    Answer:

    16×3=48

    16×5=80

    48-80=48

    then the p is 48

    0
    2021-09-17T07:43:48+00:00

    Answer:

    x² + y² – 4x – 11y + 28 = 0

    Step-by-step explanation:

    P = x,y

    A = 1,6

    B = 3,5

    APB = 90°

    which implies it is a right angled triangle having a right angle at P

    PA² + PB² = AB²

    (x – 1)² + (y – 6)² + (x – 3)² + (y – 5)² = (1-3)² + (6-5)²

    after solving you will get,‌‍‌

    2x² + 2y² – 8x – 22y + 61 = 5

    2x² + 2y² – 8x – 22y + 56 = 0

    divide 2 on both sides

    x² + y² – 4x – 11y + 28 = 0

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