Name WORKSHEET 4 Class6 Sec-c 3. Playing with Numbers 1. Find the greatest number that will divide 328, 4

Question

Name
WORKSHEET 4
Class6
Sec-c
3. Playing with Numbers
1.
Find the greatest number that will divide
328, 436 and 544 leaving remainder 7, 8 and
9 respectively,
Solution:

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Alexandra 1 month 2021-08-19T09:00:27+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-19T09:01:41+00:00

    Answer:

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________

    • We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.Now..=> 328 – 7 = 321=> 436 – 8 = 428=> 544 – 9 = 535Now.. we have to find the H.C.F. of 321, 428, 535• HCF of 321 = 3 × 107• HCF of 428 = 2 × 2 × 107• HCF of 535 = 5 × 107107 is common in 321, 428 and 535.So, HCF is 107__________________________107 is the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively

    0
    2021-08-19T09:01:51+00:00

    Answer:

    107 is the greatest number that will divide 328, 436 and 544 leaving remainder 7, 8 and 9 respectively

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