Number of solutions of the equation sinx = cos 4x for 0<=x<=π​

Question

Number of solutions of the equation sinx = cos 4x for 0<=x<=π​

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Katherine 1 week 2021-09-12T18:15:37+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-09-12T18:17:00+00:00

    Answer:

    sin

    4

    x+cos

    4

    x=sinx.cosx

    ⇒(sin

    2

    x+cos

    2

    x)−2sin

    2

    .cos

    2

    x=sinx.cosx

    ⇒1−

    2

    sin

    2

    2x

    =

    2

    sin2x

    ⇒sin

    2

    2x+sin2x−2=0

    ⇒(sin2x−1)(sin2x+2)=0

    =sin2x=−2(notpossible)

    =sin2x=1

    =2x=

    2

    π

    ,

    2

    =x=

    4

    π

    ,

    4

    I hope help you

    Step-by-step explanation:

    please me a brainlist

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