## Out of a total of 10 students, the average weight of 9 students is 60 kg. If the Weight of the 10”‘ student is 9 kg more than the average we

Question

Out of a total of 10 students, the average weight of 9 students is 60 kg. If the Weight of the 10”‘ student is 9 kg more than the average weight of all the 10 students, then the weight of 10”‘ student would be :​

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1 month 2021-08-12T10:32:28+00:00 2 Answers 0 views 0

1. Step-by-step explanation:

Average = sum/number *of quantities.

Here,

=> Average weight = (sum of weight of 9 sts)/9

=> 60 = (sum of weight of 9 students)/9

=> 540 = sum of weight of 9 students

Let the average weight of 10 students be ‘a’.

So, as said,

Weight 10th student = a + 9

Thus,

=> average weight of 10 students = a

=> (weight of 9 students + 10th stude.) = a

=> (540 + a + 9)/10 = a

=> 549/10 + a/10 = a

=> 54.9 = a – 0.1a

=> 54.9 = 0.9a

=> 54.9/0.9 = a

=> 61 = a

=> 61+9 = a +9 = weight of 10th student

=> 70 = weight of 10th studenta

• Total Students = 10
• Average of 9 Students = 60 kg
• Weight of 10th Student is 9 kh more than Average weight of all 10 Students.
• Find Weight of 10th Student.

If we can find Average of all 10 students, then we can calculate weight of 10th student easily. (By Adding 9 kg to it) i.e. Given above.

Average of 9 Students is 60 kg.

Weight of 10th Student exceed by 9 kg of Average of all 10 students weight.

That 9 kg is excess over Average Weight. Hence it will be distributed among all Students excluding 10th Student. Hence it will Increase Average by :       