polinamial p(0( p1 p2 p t =2+t+2t-t²​

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polinamial p(0( p1 p2 p t =2+t+2t-t²​

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Hadley 2 weeks 2021-09-06T04:28:34+00:00 1 Answer 0 views 0

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    2021-09-06T04:30:18+00:00

    Answer:Given polynomial is


    p(t) = 2 + t + 2t^2 – t^3


    Now,  


    p(0) = 2 + 0 + 2(0)^2 – (0)^3 = 2


    p(1) = 2 + 1 + 2(1)^2 – (1)^3 = 4


    p(2) = 2 + 2 + 2(2)^2 – (2)^3 = 4


    Therefore, values of p(0), p(1) and p(2) are 2 , 4 and 4 respectively

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