Product of first n natural number =2^a×3^b×5^c×7^d then find the value of a+b+c+d

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Product of first n natural number =2^a×3^b×5^c×7^d then find the value of a+b+c+d

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Ruby 3 weeks 2021-10-07T13:25:06+00:00 1 Answer 0 views 0

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    2021-10-07T13:26:39+00:00

    Step-by-step explanation:

    product of first n natural no.s = n(n+1)/2

    in question it is given as 2^a × 3^b ×5^c ×7^d

    so n(n+1)/2 = 2^a ×3^b ×5^c ×7^d

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