prove that by using situable identities-100-100/100-100=2 where 100-100 is not equal to 0​

Question

prove that by using situable identities….100-100/100-100=2 where 100-100 is not equal to 0​

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Elliana 5 months 2021-12-29T17:07:02+00:00 2 Answers 0 views 0

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  1. Elliana
    0
    2021-12-29T17:08:18+00:00
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    \mathfrak{dear\;user }

    \mathfrak{question-}prove 100-100/100-100=2 ​

    \mathfrak{here\:is\:the\:solution\:for \:the question }

    a^{2}-b^{2} =(a+b)(a-b)

    = (100-100)\div (100-100)=2

    L.H.S

    =(10^{2} -10^{2})\div10(10-10)

    =(10+10)(10-10)\div10(10-10) cancel[tex](10-10)[/tex]from \:numerator \:and \:denominatior.

    =10+10\div10

    =20 \div 10

    =2

    R.H.S=2

    \mathcal{MY\:EXPECTATION\: FOR \:THIS \: ANSWER \:IS }10\:thanks\:and \:brainlist

    \mathcal{BY \:ROSHAN\: A \:USER \: OF \: BRAINLY}

                                                                                        ʙʀᴀɪɴʟʏ  ʀᴏsʜᴀɴ

  2. Elliana
    0
    2021-12-29T17:08:41+00:00
    Reply

    Answer:

    gwrgerhe5u3u32y25eueu5eu6

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