prove that the square of any term of the arithmetic sequence 7,11,15 doesn’t belong to the sequence​

Question

prove that the square of any term of the arithmetic sequence 7,11,15 doesn’t belong to the sequence​

in progress 0
Eloise 4 weeks 2021-08-18T23:24:22+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-18T23:26:14+00:00

    Answer:

    It is proved that the square of any term of the arithmetic sequence 7,11,15 doesn’t belong to the sequence​.

    Step-by-step explanation:

    Given arithmetic sequence is 7,11,15

    Here, a= 7

              d = 11-7 = 4

         Tₙ = a + (n-1)d

       Let Tₙ = 49 (7 square)

              49 = 7+ (n-1)4

              42 = (n-1) 4

                n-1 = 21/2

                   n = 21/2 + 1

                   n = 23/2

              But ‘n’ can not be a fractional/rational number.

                 Therefore n=23/2 is impossible.

          It implies that 49 is not a term of the given AP.

    Try these steps for 121 and 225 also. You will get it.

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )