prove that the square of any term of the arithmetic sequence 7,11,15 doesn’t belong to the sequence Question prove that the square of any term of the arithmetic sequence 7,11,15 doesn’t belong to the sequence in progress 0 Math Eloise 4 weeks 2021-08-18T23:24:22+00:00 2021-08-18T23:24:22+00:00 1 Answer 0 views 0

## Answers ( )

Answer:It is proved that the square of any term of the arithmetic sequence 7,11,15 doesn’t belong to the sequence.

Step-by-step explanation:Given arithmetic sequence is 7,11,15

Here, a= 7

d = 11-7 = 4

Tₙ = a + (n-1)d

Let Tₙ = 49 (7 square)

49 = 7+ (n-1)4

42 = (n-1) 4

n-1 = 21/2

n = 21/2 + 1

n = 23/2

But ‘n’ can not be a fractional/rational number.

Therefore n=23/2 is impossible.

It implies that 49 is not a term of the given AP.

Try these steps for 121 and 225 also. You will get it.