Q-1 The area of rombus is 119cm² and it’s perimeter is 56cm. Find it’s height. Q-2 The area of rombus is 44

Question

Q-1
The area of rombus is 119cm² and it’s perimeter is 56cm.
Find it’s height.

Q-2
The area of rombus is 441cm² and it’s height is 17.5cm. Find the length of each side of the rombus.

Q-3
The area of a rhombus is
equal to the area of triangle having base 24.8 cm and the corresponding height 16.5cm. If one of its diagonal of the rhombus is 22cm find the length of the other diagonal.

Hello Guys ☺️

Please answer the question fast

-@Aparna Priyadarshini

in progress 0
Raelynn 4 weeks 2021-08-14T06:51:22+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-14T06:52:50+00:00

    Step-by-step explanation:

    1. area of rombus = 119cm²

    perimeter = 56cm.

    56 = 4 * side

    side = 56/4 = 14cm

    119cm²= 14*height

    height = 119/14 = 8.5cm

    2. area of rombus = 441cm²

    height = 17.5cm.

    441cm²= 17.5*side

    side= 441/17.5 = 25.2cm

    3.

    the area of triangle = base * height

    = 24.8*16.5 = 409.2cm²

    area of triangle = area of rhombus = 409.2cm²

    d1 of rhombus = 22cm

    area of a rhombus = d1*d2

    409.2cm²= 22cm *d2

    d2= 409.2/22

    d2 = 18.6cm

    follw me if you like

    0
    2021-08-14T06:53:11+00:00

    \star\;\;{\underline{\underline{\bf{\pink{Question\;1\;-}}}}}

    The area of rombus is 119cm² and it’s perimeter is 56cm. Find it’s height.

    GivEn:-

    • Area of rhombus = 119cm²
    • Perimeter of rhombus = 56cm

    To find:-

    • Height of rhombus

    SoluTion:-

    As we know that,

    ☯ Perimeter of rhombus = 4 × length of its side

    \therefore All side of rhombus are euqal!

    :\implies Length of its side = \sf \dfrac{Perimeter}{4}

    :\implies Length of its side = \sf \cancel{ \dfrac{54}{4}}

    :\implies Length of its side = 14cm

    ☯ Area of rhombus = base(side) × Altitude

    :\implies Altitude = \sf \dfrac{Area}{Base}

    :\implies Altitude = \sf \cancel{ \dfrac{119}{14}}

    :\implies Altitude = 8.5 cm

    \dag Hence, Altitude of rhombus is 8.5 cm.

    ▬▬▬▬▬▬▬▬▬▬

    \star\;\;{\underline{\underline{\bf{\pink{Question\;2\;-}}}}}

    The area of rombus is 441cm² and it’s height is 17.5cm. Find the length of each side of the Rhombus.

    GivEn:-

    • Area of rhombus = 441cm²
    • Height of rhombus = 17.5 cm

    To find:-

    • length of each side of the Rhombus.

    SoluTion:-

    As we know that,

    ☯ Area of rhombus = Side × Altitude

    :\implies Side = \sf \dfrac{Area}{Altitude}

    :\implies Side = \sf \dfrac{441}{17.5}

    :\implies Side = 25.2 cm

    \dag Hence, Side of rhombus is 25.2 cm.

    ▬▬▬▬▬▬▬▬▬▬

    \star\;\;{\underline{\underline{\bf{\pink{Question\;3\;-}}}}}

    The area of a rhombus is equal to the area of triangle having base 24.8 cm and the corresponding height 16.5cm. If one of its diagonal of the rhombus is 22cm find the length of the other diagonal.

    GivEn:-

    • Area of rhombus = Area of triangle
    • Base of rhombus = 24.8 cm
    • Height of rhombus = 16.5 cm
    • One of the diagonal of rhombus = 22cm

    To find:-

    • Length of other diagonal.

    SoluTion:-

    Let other diagonal of rhombus be x cm.

    GivEn that,

    ☯ Area of rhombus = Area of triangle

    :\implies\sf \dfrac{1}{2} \times base \times height = \dfrac{Product\;of\;diagonals}{2} \quad\bigg\lgroup\bf By\; Deriving\;the\;formula \bigg\rgroup

    :\implies\sf \dfrac{1}{2} \times 24.8 \times 16.5 = \dfrac{22 \times x}{2}

    :\implies\sf 204.6 \times 2 = 22 \times x

    :\implies\sf \dfrac{204.6 \times 2}{22} = x

    :\implies\sf \dfrac{409.2}{22} = x

    :\implies x = 18.6 cm

    \dag Hence, Length of diagonal is 18.6 cm.

    ▬▬▬▬▬▬▬▬▬▬

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )