Q: If x is real then the minimum value of (x^2-x-1) is: (A) 1 (B) -5/4 (C)3/4 (D) 0​

Question

Q: If x is real then the minimum value of (x^2-x-1) is:
(A) 1
(B) -5/4
(C)3/4
(D) 0​

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Brielle 4 weeks 2021-08-18T02:53:25+00:00 1 Answer 0 views 0

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    0
    2021-08-18T02:55:21+00:00

    Answer:

    Maybe 1 is the answer or 0

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18:9+8+9*3-7:3-1*13 = ? ( )