q3: Shikha is 30 years older than her son. I year ago she was four times as old as her son. Find their present a

Question

q3: Shikha is 30

years older than her son. I year ago she was
four
times as old as her son. Find
their present ages.​

in progress 0
Remi 1 month 2021-08-14T05:48:28+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-14T05:49:29+00:00

    Let , the age of son be ” x “

    First Condition :

    Shikha is 30 years older than her son

    Thus ,

    Shikha’s age = ” x + 30 “

    Second Condition :

    1 year ago she was four times as old as her son

    Thus ,

    (x + 30 – 1) = 4(x – 1)

    x + 29 = 4x – 4

    33 = 3x

    x = 33/3

    x = 11

     \therefore The present ages of shikha and her son are 11 and 41

    0
    2021-08-14T05:50:01+00:00

    Answer:

    \red{\bf{\dag Age \:of\:Shikha=41\:yrs}}

    \red{\bf{\dag Age \:of\: son=11\:yrs}}

    Step by step explanation:

    Given:

    • Shikha is 30 years older than her son.
    • 1 year ago she was four times as old as her son.

    To Find:

    • Their present ages.

    Answer:

    Let us take the present age of son be x .

    Then the present age of Shikha will be (x+30) .

    Now ,

    • Age of Shikha 1 year ago = (x+30)-1=x+29.
    • Age if son one year ago = (x-1).

    Atq,

    \sf{\implies 4(x-1) = x+29}

    \sf{\implies 4x - 4 = x + 29 }

    \sf{\implies  4x - x = 29+4}

    \sf{\implies 3x = 33 }

    \sf{\implies x = \dfrac{33}{3}}

    \bf{\leadsto x = 11 }

    Hence

    • Present age of Shikha = x+30 = 11+30=41 years.
    • Present age of son = x = 11 years.

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