## rehman has 50 coins in his purse which are of 20 paisa and 25 paisa denomination. The value of all coins is Rs. 11.25 find the number of cou

Question

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## Answers ( )

Answer:–Given:

Total number of coins = 50

Let the number of 20 P coins be

xand number of 25 P coins bey## → x + y = 50 — equation (1)

And,

The value of all the coins = Rs. 11.25

Value of 20 P coins = 20* x = 20x P

Value of 25 P coins = 25 * y = 25y P

Hence,

20x + 25y = 11.25 * 100 P

→ 5 (4x + 5y) = 1125 P

→ 4x + 5y = 1125 / 5

## → 4x + 5y = 225 — equation (2)

Multiply equation (1) by 4 and subtract equation (1) from (2).

→ 4x + 5y – 4 ( x + y) = 225 – 4(50)

→ 4x + 5y – 4x – 4y = 225 – 200

## → y = 25

→

Number of 20 P coins = 25Substitute the value of y in equation (1)

→ x + y = 50

→ x + 25 = 50

→ x = 50 – 25

## → x = 25

→

Numberof25Pcoins=25Hence,there25–25Pcoinsand25–20PcoinsalongwithRehman.