resolve into factors (x^2 + 4x)^2 + 4x^2 – 2x^2y + 16x – 8xy​

Question

resolve into factors
(x^2 + 4x)^2 + 4x^2 – 2x^2y + 16x – 8xy​

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Everleigh 2 weeks 2021-09-07T04:52:12+00:00 1 Answer 0 views 0

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    2021-09-07T04:53:44+00:00

    Step-by-step explanation:

     {( {x}^{2}  + 4x)}^{2}  + 4 {x}^{2}  - 2 {x}^{2} y + 16x - 8xy

     =  {( {x}^{2} + 4x )}^{2} + (4 {x}^{2}   + 16x) - (2 {x}^{2} y + 8xy)

     =   {x}^{2} {( x  + 4)}^{2}  + 4x(x+ 4)  - 2xy( x + 4)

     = (x + 4)( {x}^{2} .(x + 4) + 4x - 2xy)

     = (x + 4)( {x}^{3}  + 4 {x}^{2}  + 4x - 2xy)

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