sinAsinB+secAcos/cosAcosecB – sin^B/cos^A If A+B = 90 Find the value of sinAsinB+secAcosB/cosAcosecB – sin^2B/cos^2A

Question

sinAsinB+secAcos/cosAcosecB – sin^B/cos^A
If A+B = 90
Find the value of sinAsinB+secAcosB/cosAcosecB – sin^2B/cos^2A

in progress 0
Mia 1 week 2021-09-14T06:34:25+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-14T06:36:02+00:00

    Answer:

    588(88)

    585-5884=8885

    sz5885(588-58)

    ab=585-58+58=88

    0
    2021-09-14T06:36:09+00:00

    Answer:

    We know that the maximum value of sinxsinxis 1. So, we see that the only possible values of A and B is that when both sinA and sinB achieve their maximum values which is possible only when sinA=1sin⁡A=1andsinB=1sin⁡B=1

    Thus, A=2A=2kπ+π/2andB=2mπ+π/2kπ+π/2andB=2mπ+π/2

    Thus

    cosA+cosBcos⁡A+cos⁡B

    =cos(2kπ+π/2)+cos(2mπ+π/2)=cos⁡(2kπ+π/2)+cos⁡(2mπ+π/2)

    =0+0=0+0

    =0

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )