solve, 1 /3a+b+3x = 1/ 3a + 1 /b +1 /3x​

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solve, 1 /3a+b+3x = 1/ 3a + 1 /b +1 /3x​

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Lydia 3 days 2021-09-14T09:43:36+00:00 1 Answer 0 views 0

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    2021-09-14T09:45:14+00:00

    Answer:

    in this question

    first we take similar terms in one side

    1/3a+ b+ 3x = 1/3a+ 1/b + 1/3x

    1/3a + b + 3x – 1/3a – 1/b -1/3x = 0

    1/3a is cancel with 1/3a and we break b and 3x in equal parts means b= 1/b and 1/b , 3x = 1/ 3x and 1/3x .

    the remaining is

    1/b + 1/b – 1/b +1/3x +1/3x – 1/3x = 0

    1 / b is cross with – 1/b and 1/3x is also cross with -1/3x

    the remaining is 1/b + 1/3x it is answer of this question

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