Solve by splitting the middle term -n2+5n+14

Question

Solve by splitting the middle term -n2+5n+14

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Emery 3 weeks 2021-09-07T06:59:48+00:00 2 Answers 0 views 0

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    0
    2021-09-07T07:00:51+00:00

    Answer:

     -  {n}^{2}  + 5n + 14 = 0 \\  \\ multiplying \: by \:  - 1 \\  \\  {n}^{2}  - 5n - 14 = 0 \\  \\  {n}^{2}  + 2n - 7n - 14 = 0 \\  \\ n(n + 2) - 7(n + 2) \\  \\ (n + 2) \:  \: (n - 7) = 0 \\  \\ n =  - 2 \:  \:  \: or \:  \:  \: n = 7

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    0
    2021-09-07T07:01:16+00:00

     { - n}^{2}  + 5n + 14 = 0

    divide both side with. -1

    n^2 -5n -14=0

    n^2 -7n+2n-14=0

    n(n-7) +2(n-7)=0

    (n+2) (n-7) =0

    n= -2 and n= 7

    this is correct solution

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