solve for a and b: 47a+31b=63 31a+47b=15 Question solve for a and b: 47a+31b=63 31a+47b=15 in progress 0 Math Eliza 5 days 2021-09-13T15:51:54+00:00 2021-09-13T15:51:54+00:00 1 Answer 0 views 0

## Answers ( )

Answer:47x + 31y = 63 ……………1

31x + 47y = 15 ……………2

Multiply equation 1 by 31 and equation 2 by 47, we get

47 * 31x + 31 * 31y = 63*31 ……………3

31 * 47x + 47 * 47y = 15*47 ……………4

Subtraction equation 3 by 4, we get

(47 * 31x + 31 * 31y) – (31 * 47x + 47 * 47y) = 63*31 – 15*47

=> 47 * 31x + 31 * 31y – 31 * 47x – 47 * 47y = 63*31 – 15*47

=> 31 * 31y – 47 * 47y = 63*31 – 15*47

=> 961y – 2209y = 1953 – 705

=> -1248y = 1248

=> y = -1248/1248

=> y = -1

From equation 1, we get

47x + 31 * (-1) = 63

=> 47x – 31 = 63

=> 47x = 63 + 31

=> 47x = 94

=> x = 94/47

=> x = 2

Hence, x = 2, y = -1

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