solve the equation Q2. 7z – 18 = 2 – 28 + 2z​

Question

solve the equation Q2. 7z – 18 = 2 – 28 + 2z​

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Eden 2 weeks 2021-09-10T10:20:09+00:00 1 Answer 0 views 0

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    2021-09-10T10:21:48+00:00

    Q2) 7z – 18 = 2 – 28 + 2z

    => 7z – 2z = 2- 28 +18

    => 5z = 20 -28

    => 5z = -8

    => z = -8/5

    Now,

    verify the equation:-

    =>7z – 18 = 2 – 28 + 2z

    => 7(-8/5) – 18 = 2 – 28 + 2(-8/5)

    => -56/5 – 18 = – 26 – 16/5

    => -56 -90/5 = -130-16/5

    => -146/5 = -146/5

    LHS = RHS

    Linear equation in one variable :- it is an equation which is formed in the az + b = 0 where, A and B are two integers and z is only one variable so, it has only one solution.

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