solve the equation Q2. 7z – 18 = 2 – 28 + 2z Question solve the equation Q2. 7z – 18 = 2 – 28 + 2z in progress 0 Math Eden 2 weeks 2021-09-10T10:20:09+00:00 2021-09-10T10:20:09+00:00 1 Answer 0 views 0

## Answers ( )

Q2) 7z – 18 = 2 – 28 + 2z

=> 7z – 2z = 2- 28 +18

=> 5z = 20 -28

=> 5z = -8

=> z = -8/5

Now,

verify the equation:-

=>7z – 18 = 2 – 28 + 2z

=> 7(-8/5) – 18 = 2 – 28 + 2(-8/5)

=> -56/5 – 18 = – 26 – 16/5

=> -56 -90/5 = -130-16/5

=> -146/5 = -146/5

LHS = RHS

Linear equation in one variable :- it is an equation which is formed in the az + b = 0 where, A and B are two integers and z is only one variable so, it has only one solution.