solve the following quadratic equation for x √6x+7-(2x-7)=0​

Question

solve the following quadratic equation for x √6x+7-(2x-7)=0​

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Faith 1 month 2021-08-21T13:17:23+00:00 1 Answer 0 views 0

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    0
    2021-08-21T13:18:45+00:00

    Answer:

    Step-by-step explanation:

    Hi,

    Sqrt (6x +7) – (2x – 7 ) = 0

    sqrt ( 6x + 7 ) = ( 2x – 7 )

    ———————-Squaring both side———————————–

    ( sqrt ( 6x + 7 ))^2 = ( 2x – 7 )^2

    6x + 7 = 4x^2 -28x +49

    0 = 4x^2 -28x -6x +49 – 7

    4x^2 -34x +42 = 0

    Divide each term with 2

    2x^2 – 17x +21 = 0

    2x^2 – 14x – 3x +21 = 0

    2x ( x – 7 ) – 3( x – 7 ) = 0

    ( x – 7 ) ( 2x – 3 ) = 0

    x – 7 = 0 or 2x – 3 = 0

    x = 7 or 2x = 3

    x = 7 or x = 3/2

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