Solve the system of equations bx/a-ay/b+a+b=0 and bx-ay+2ab=0

Question

Solve the system of equations bx/a-ay/b+a+b=0
and bx-ay+2ab=0

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Reagan 1 week 2021-09-11T04:10:45+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-09-11T04:12:16+00:00

    Answer:

    We have,

    bx/a – ay/b+a+b=0……… (1)

    And bx-ay+2ab = 0……….(2)

    Dividing (2) by b and then substracting from (1) we get

    bx/a-x + a+b-2a =0

    => (b-a)x/a + b – a =0

    => x = – a

    Putting x in (2) we get

    -ab – ay +2ab =0

    => y = b

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