## state whether the following quadratic equations have two distinct real roots justify your answer. root 2X^2 – (3/root 2) + 1

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## Answers ( )

A quadratic equation, ax2 + bx + c = 0; a ≠ 0 will have two distinct real roots if its discriminant, D = b2 – 4ac > 0. Hence, the equation x2 –3x + 4 = 0 has no real roots. … Hence, the equation 3×2 – 4x + 1 = 0 has two distinct real roots.

Answer:= X1 = – ⁴√8/2 and X2 = ⁴√8/2 .

Que:2x²-3/√2+1/√2 = 0★Solution:Rationalisethe denominator= 2x²-3/√2+1/√2 = 0

= 2x²-3√2/√2+1/√2 = 0

= 2x²-3√2/2+√2/2 = 0

= 2x²- √2 = 0

= 2x² = √2

= x² = √2/2

= x = ± ⁴√8/2

=

X1= – ⁴√8/2 andX2= ⁴√8/2 .