Subtract 3×2+5y2-2y2 from the sum of 5y2+3z2 and 2×2-3y2

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Subtract 3×2+5y2-2y2 from the sum of 5y2+3z2 and 2×2-3y2

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Nevaeh 1 month 2021-08-20T10:22:00+00:00 1 Answer 0 views 0

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    2021-08-20T10:23:58+00:00

    the sum of (5y²+3z²)+ (2x²-3y²)

    is 2x²2y²+3z²

    the difference is (3x²+5y²-2y²) – (2x²2y²+3z²)

    is (x²+7y²-5z²

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